A card is drawn from pack of cards what is the probability of getting spade or pictured card.

Pack of cards $=52$
Spades $=13$
Pictured cards$=4\times 3=12$
A card is drawn from a pack of cards so  $n\left(S\right)=52$

i) $A$ be the event of selecting a spade

$n\left(A\right){=}^{13}{C}_1$

$P\left(A\right)=\frac{n\left(A\right)}{n\left(S\right)}=\frac{13}{52}=\frac{1}{4}$

ii) $B$ be the event of selecting a pictured card

$n\left(B\right){=}^{12}{C}_1$

$P\left(B\right)=\frac{n\left(B\right)}{n\left(S\right)}=\frac{{ }^{12}{C}_1}{{ }^{52}{C}_1}=\frac{12}{52}$

iii) $A\cap B$ is the event of pictured spade

$$\begin{gathered} n(A\cap B)=3 \\ P(A\cap B)=\frac{n(A\cap B)}{n\left(S\right)}=\frac{3}{52} \end{gathered}$$

$iv) P(A\cup B)=P(A)+P(B)-P(A\cap B)$

$=\frac{13}{52}+\frac{12}{52}-\frac{3}{52}=\frac{22}{52}=\frac{11}{26}$