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A card is randomly selected from a pack of 52 cards and the card is not replaced. Then a second card is chosen. Find the probability that first card is red and second card is black

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\frac{23}{102}

\frac{28}{102}

\frac{26}{104}

\frac{26}{102}

answer is D.

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Detailed Solution

As we know that,
Probability =

\frac{Total favourable outcomes}{Total outcomes}

A pack of 52 cards contains 26 black cards and 26 red cards. It contains 13 hearts, 13 clubs, 13 diamonds, 13 spades.
Probability of first card is red and the second is black
= probability that first card is red probability the second is black

= \frac{26}{52} \times \frac{26}{51} = \frac{26}{102}

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