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Q.

A Carnot engine absorbs 750J of heat energy from a reservoir at 137°C and rejects 500J of heat during each cycle, then the temperature of sink is

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a

0.25°C

b

0.44°C

c

0.34°C

d

0.54°C

answer is B.

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Detailed Solution

1- $\frac{Q_{1}}{Q_{2}}$ = 1 + $\frac{T_{1}}{T_{2}}$

$\frac{Q_{1}}{Q_{2}}$ = $\frac{T_{1}}{T_{2}}$

$\frac{750}{500} = \frac{410}{T_{2}}$

T₂ = $\frac{410 \times 500}{750} = 273.34 K$

= 273 - 273.34 = 0.34⁰C

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