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A Carnot engine has efficiency of 50%. If the temperature of sink is reduced by 40°C, its efficiency increases by 30%. The temperature of the source will be:

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166.7 K

367.7 K

255.1 K

266.7 K

answer is C.

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Detailed Solution

$\begin{array}{l} 1 - \frac{T_{L}}{T_{H}} = 0 .5 \\ 1 - \frac{T_{L} - 40}{T_{H}} = 0 .65 \\ \Rightarrow T_{H} = \frac{800}{3} K = 266 .7 K \end{array}$

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