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Q.

A Carnot engine having an efficiency of $\frac{1}{20}$ as heat engine, is used as a refrigerator. If the work done on the system is $20 J$ , the amount of energy absorbed from the reservoir at lower temperature is :-

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a

$380 J$

b

$399 J$

c

$400 J$

d

$10 J$

answer is A.

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Detailed Solution

$β = \frac{Q_{2}}{W} = \frac{1 - η}{η} \Rightarrow \frac{Q_{2}}{20} = \frac{1 - 0.05}{0.05} = 19 \Rightarrow Q_{2} = 19 \times 20 = 380 J$

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A Carnot engine having an efficiency of 120 as heat engine, is used as a refrigerator. If the work done on the system is 20 J, the amount of energy absorbed from the reservoir at lower temperature is :-