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A Carnot engine take $5000 kcal$ of heat from a reservoir at $727 ° C$ and gives heat to a sink at $127 ° C$ . The work done by the engine is :

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$3 \times 10^{6} J$

zero

$12.6 \times 10^{6} J$

$8.4 \times 10^{6} J$

answer is C.

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Detailed Solution

$L = \frac{WD}{Q_{H}}$
$\Rightarrow WD = Q_{H} (1 - \frac{T_{L}}{T_{H}})$
$= 5 \times 10^{3} (1 - \frac{400}{1000})$
$= 3000 kcal$

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