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A Carnot engine takes in 3000 kcal of heat from a reservoir at 627Â°C and gives it to a sink at 27Â°C. The work done by the engine is

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4.2 x 10⁶ J

8.4 x 10⁶J

16.8 x 10⁶J

zero

answer is B.

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Detailed Solution

$Î· = \frac{T_{1} â T_{2}}{T_{1}} = \frac{900 â 300}{900} = \frac{2}{3}$
work done
$\begin{array}{l} W = Î·Q = \frac{2}{3} Ã (3000 Ã 10^{3} Ã 4 â 2) \\ = 8 â 4 Ã 10^{6} J \end{array}$

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