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Q.

A Carnot engine, whose efficiency is $40 %,$ takes in heat from a source maintained at a temperature of $500 K.$ It is desired to have an engine of efficiency $60 % .$ Then, the intake temperature for the same exhaust (sink) temperature must be – (in Kelvin)

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answer is 750.

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Detailed Solution

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For 1st case,

$\begin{array}{l} Efficiency = η = (1 - \frac{T_{1}}{T_{2}}) \times 100 \\ (1 - \frac{T_{1}}{500}) \times 100 = 40 \\ T_{1} = 300 K \end{array}$

For 2nd case,

$η = (1 - \frac{300}{T_{2}}) \times 100 = 60$

$T_{2} = 750 K$

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A Carnot engine, whose efficiency is 40%, takes in heat from a source maintained at a temperature of 500 K. It is desired to have an engine of efficiency 60%.Then, the intake temperature for the same exhaust (sink) temperature must be – (in Kelvin)