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Q.

A Carnot engine whose heat sinks at 27°C, has an efficiency of 25%. By how many degrees should the temperature of the source be changed to increase the efficiency by 100% of the original efficiency?

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a

Increases by 18°C

b

Increase by 120°C

c

Increase by 73°

d

Increase by 200°C

answer is B.

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Detailed Solution

Question Image

1−300T=0.25300T=0.75T=400K 

If efficiency increased by 100% then new efficiency ⇒ n’ = 50%

 1−300T′=0.5 T′=600K

Increase in temp = 600 – 400

= 200 K or 200°C

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