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A Carnot engine working between 300 K and 600 K has work output of 700 J per cycle. What is amount of heat energy supplied to the engine from source per cycle

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1000 J/cycle

2000 J/cycle

1800 J/cycle

1400 J/cycle

answer is D.

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Detailed Solution

$η = \frac{T_{1} - T_{2}}{T_{1}} = \frac{w}{Q}$

$Q = w (\frac{T_{1}}{T_{1} - T_{2}}) = 700 (\frac{600}{600 - 300})$

$= 1400 J$

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