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A Carnot engine working between $400 K$ and $800 K$ has a work output of $1200 J$ per cycle. The amount of heat energy (in $j o u l e s$ ) supplied to the engine from source per cycle is

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$2500$

$2600$

$2400$

$2700$

answer is A.

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Detailed Solution

$W = 1200 J, T_{1} = 800 K, T_{2} = 400 K η = 1 - \frac{T_{2}}{T_{1}} = \frac{W}{Q_{1}} 0.5 = \frac{1200}{Q_{1}}$

Heat energy supplied by source $Q_{1} = \frac{1200}{0.5} = 2400 J$

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