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Q.

A carnot’s cycle operates at source temperature 9270C. In each stage compression or expansion volume is in the ratio 1:32  (γ=1.4). Efficiency in % is 

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answer is 75.

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Detailed Solution

T1V1y−1=T2V2y−1⇒T2=(V1V2)r−1 T1=(125)0.4 T1=T14

=927+2734=300k

η=1−T2T1=1−3001200=1−14=34=75%

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