A Carnot’s engine working between 400K and 800K has a work output of 1200 J per cycle. The amount of heat energy supplied to the engine from the source in each cycle is:

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1600 J

3200 J

1800 J

2400 J

answer is B.

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Detailed Solution

$\begin{array}{l} Efficiency of Carnot's engine \\ η = (1 - \frac{T_{2}}{T_{1}}) = \frac{W}{Q} \\ \Rightarrow (1 - \frac{400}{800}) = \frac{1200}{Q} \\ \Rightarrow \frac{1}{2} = \frac{1200}{Q} \\ \Rightarrow Q = 2400 J \end{array}$

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