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A catalyst lowers the activation energy from $20 kJ {mol}^{- 1}$ to $15 kJ {mol}^{- 1}$ of the forward direction of the reaction $A ⇌ B$ . Which of the following statement regarding the reaction is correct?

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Activation energy of the backward direction is increased by

5 kJ {mol}^{- 1}

Activation energy of the backward direction is decreased by

5 kJ {mol}^{- 1}

Enthalpy ofreaction is increased by

5 kJ {mol}^{- 1}

Equilibrium constant of the reaction is decreased

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detailed solution

Correct option is B

Energy of backward reaction is also decreased by $5 kJ {mol}^{- 1}$ without affecting the value of $Δ H$ and $K_{eq}$ of the reaction.

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A catalyst lowers the activation energy from 20 kJ mol−1to 15 kJ mol−1 of the forward direction of the reaction A⇌B. Which of the following statement regarding the reaction is correct?

Unlock the full solution & master the concept.

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A catalyst lowers the activation energy from $20 kJ {mol}^{- 1}$ to $15 kJ {mol}^{- 1}$ of the forward direction of the reaction $A ⇌ B$ . Which of the following statement regarding the reaction is correct?