A cell constructed by coupling a standard copper electrode and a standard magnesium electrode has emf of 2.7 volts. If the standard reduction potential of copper electrode is +0.34 volt, that of magnesium electrode is

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+ 3.04 volts

+ 2.36 volts

– 3.04 volts

– 2.36 volts

answer is D.

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Detailed Solution

Mg lies above Cu in electrochemical series and hence Cu electrode acts as cathode.

$E_{c e l l}^{o} = E_{c a t h o d e}^{o} - E_{a n o d e}^{o} 2.7 = 0.34 - E_{M g 2 + / M g}^{o} E_{M g^{2 +} / M g}^{o} = - 2.36 V$

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