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A cell has 80pg of DNA and 10 chromosomes in the $G_{1}$ phase. Calculate the number of chromosome and the amount of DNA in at the end of S phase.

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80 pg DNA and 10 chromosomes

160pg DNA and 20 chromosomes

80 pg DNA and 20 chromosomes

160 pg DNA and 10 chromosomes

answer is D.

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Detailed Solution

During the S phase the number of chromosomes remain the same but the amount of DNA doubles.
Therefore, the amount of DNA becomes 80 X 2=160 pg and the no. of chromosomes still remains the same, i.e., 10 chromosomes.

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