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Q.

A cell in an open circuit has e.m.f. of 2V and in closed circuit having a current of 0.05 A the p.d. is 1.5 V. Then the internal resistance is

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a

10Ω

b

6Ω

c

20Ω

d

5Ω

answer is C.

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Detailed Solution

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E−V=ir;r=E−Vi=2−1.50.05=0.50.05=10Ω

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