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A cell of emf 12 volt is balanced by a length of 60 cm of a potentiometer wire. Now the wire of the potentiometer is replaced by another wire of same length but of radius twice the radius of the previous wire. Then the balancing length of a 18 volt cell will be

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84 cm

90 cm

40 cm

72 cm

answer is A.

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Detailed Solution

Balancing length is independent of the radius of potentiometer wire when length is same.

$∴ \frac{18}{12} = \frac{l}{60} \Rightarrow l = 90 c m$

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