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A cell of emf 3.4 volt and internal resistance $3 Ω$ is connected to an ammeter having resistance $2 Ω$ and external resistance of $100 Ω$ . When a voltmeter is connected across the the $100 Ω$ resistance, The ammeter reading is 0.04 A. Then the resistance of the voltmeter is.

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$280 Ω$

$100 Ω$

$200 Ω$

$400 Ω$

answer is A.

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Detailed Solution

Let R be the resistance of voltmeter.

$∴ R_{eff} = (3 + 2 + \frac{100 R}{100 + R}) Ω = (5 + \frac{100 R}{100 + R}) Ω ∴ i = \frac{3 .4}{(5 + \frac{100 R}{100 + R})} = 0 .04 \Rightarrow R = 400 Ω$

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