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Q.

A cell of emf 4.5V is connected to a junction diode whose barrier potential is 0.7 V. If the external resistance in the circuit is 190Ω, then the current in the circuit is:

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a

0.2mA

b

20mA

c

2mA

d

0.02mA

answer is A.

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Detailed Solution

E = 4.5 V 
VD = 0.7 V
R = 190 Ω

The current through the circuit is

we know, I=E−VDR ⇒I=4.5−0.7190=0.02A=20 mA

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A cell of emf 4.5V is connected to a junction diode whose barrier potential is 0.7 V. If the external resistance in the circuit is 190Ω, then the current in the circuit is: