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Q.

A cell of emf 90V is connected across series combination of two resistors each of 100 $Ω$ resistance. A voltmeter of resistance 400 $Ω$ is used to measure the potential difference across each resistor .The reading of the voltmeter will be:

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a

45V

b

40 V

c

90V

d

80V

answer is C.

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Detailed Solution

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The effective resistance of 100 $Ω$ and 400 $Ω$ is given by $R_{eff} = \frac{100 \times 400}{500} = 80 Ω$

$v_{2} = \frac{80}{180} \times 90 = 40 V$

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