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A cell of emf 'E' is connected across a resistance R. The potential difference between the terminals of the cell is found to be V. The internal resistance of the cell must be :

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(E- V)R

$\frac{2 (E - V) R}{E}$

$\frac{(E - V) R}{V}$

$\frac{2 (E - V) V}{R}$

answer is C.

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Detailed Solution

$E = i (R + r) E = V + i r E = V + (\frac{E}{R + r}) r W e g e t r = \frac{(E - V) R}{V}$

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