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Q.

A cell of emf E volt with no internal resistance is connected to a wire whose cross section changes. The wire has three sections of equal length. The middle section has a radius a, whereas the radius of the outer two sections is 2A. The ratio of the potential difference across section AB to the potential difference across section CA is

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a

¼

b

½

c

4

d

5

answer is B.

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Detailed Solution

In series combination, I is constant, therefore V µ R. $\frac{V_{A B}}{V_{C A}} = \frac{R_{A B}}{R_{C A}} = \frac{ρ \frac{l}{π a^{2}}}{ρ \frac{l}{π {(2 a)}^{2}}} = 4$

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