Q.

A certain amount of mono atomic gas undergoes a process for which UβV , where U is internal energy and V is volume of gas. It is found that the ratio ΔUΔQ for the process is 13 . What is the value of β

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answer is 3.

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Detailed Solution

UβVTβVPβVβVPβVβ1= constant P(V)(β1)β= constant ΔUΔQ=ncVΔTncΔT=13C=3CVCV+R1x=3CV
Where x=β1ββ=3

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