A certain anion carries $-9.6\times {10}^{-19}$ coulombs of static electric charge. Calculate the number of electronic charges present on it.

The number of electronic charges present is 6.

$\overrightarrow{e}=1.6\times {10}^{-19}\mathrm{C}$

$q=9.6\times {10}^{-19}$

No of electron

 $e^{-}=\frac{q\left(9.6\times {10}^{-19}\right)}{e\left(1.6\times {10}^{-19}\right)}=6$.

Electric charges are of two types: Positive and Negative, commonly carried by charge carriers protons and electrons.