A certain current liberated 0.504 g of hydrogen in 2 hours. How many grams of copper can be liberated by the same current flowing for the same time in a copper sulphate solution?

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12.7 g

31.8 g

15.9 g

63.5 g

answer is C.

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Detailed Solution

$\begin{array}{l} \frac{Weight of Cu}{{Weight of H}_{2}} = \frac{Eq. weight of Cu}{Eq. weight of H} \\ \frac{Weight of Cu}{0 .50} = \frac{63 .6 / 2}{1} \\ Weight of Cu = 15.9 g \end{array}$

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