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Q.

A certain dye absorbs light of λ=4000Å and then fluorescences light of λ=5000Å. Assuming that under given conditions 50% of the absorbed energy is re-emitted out as fluorescence, calculate the ratio of the number of quanta emitted out to the number of quanta absorbed

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a

38

b

58

c

83

d

85

answer is A.

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Detailed Solution

Number of quanta emitted out to the number of quanta absorbed can be calculated as;

N1×hc4000×0.5=N2×hc5000 ⇒N2N1=58
 

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