AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A certain force exerted for $1.2 s$ raises the speed of an object from $1.8 m / s$ to $4.2 m / s$ . Later the same force is applied for $2 s$ . How much will the speed change in $2 s$ ?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

2.5 m / s

4 m / s

5 m / s

3.5 m / s

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

A certain force exerted for

1.2 s

raises the speed of an object from

1.8 m / s

4.2 m / s

. Later the same force is applied for

2 s

. The change of speed in

2 s

4 m / s

.
Given data in the problem,
Initial velocity,

u = 1.8 m / s

Final velocity,

v = 4.2 m / s

Time duration for force applied,

t = 1.2 s

By first law of motion,

v = u + at

Where,

v = final velocity

u = initial velocity

a = acceleration

t = time

And by rearranging the equation, the acceleration of a body is given as

\Rightarrow a = \frac{(v - u)}{t}

\Rightarrow a = \frac{4.2 - 1.8}{1.2}

\Rightarrow a = \frac{2.4}{1.2}

\Rightarrow a = 2 m s^{- 2}

and change of speed is given by
again, the same force applied for time,

t = 2 s

change of speed = a \times t

= 2 \times 2

= 4 m / s

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!