A certain mass of a gas is expanded from (2 L, 20 atm, 300 K] to (5 L, 10 atm, 320 K] against a constant external pressure of 5 atm, H heat capacity of the gas is 100 J/°C then enthalpy change of the process will be : (1 atm lit. = 100 J]

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1.5 kJ

2 kJ

1 kJ

0.5 kJ

answer is C.

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Detailed Solution

We known that,

$\begin{array}{l} q = C Δ T = + 2 kJ \\ w = \frac{- 5 \times 3 \times 100}{1000} = - 1.5 kJ \\ Δ U = 0.5 kJ \\ Δ H = 0.5 + \frac{10 \times 100}{1000} = 1.5 kJ \end{array}$

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