A certain mass of an ideal gas is expanded from (1L, 10 atm) to (4L, 5 atm) against a constant external pressure of 1 atm. Initial temperature of gas is 300 K and the heat
capacity of process is $50 J / {}^{0}C$ .Find out $Δ H$ in KJ of the process.
[ Given 1 atm litre =100 J]

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answer is 15.7.

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Detailed Solution

$\frac{1 \times 10}{300} = \frac{4 \times 5}{T} \Rightarrow T = 600 K$
$q = 50 \times 300 = 15 k J$
$w = - 1 (4 - 1) \times \frac{100}{1000} = - 0.3 k J$
$Δ U = 14.7 k J$
$Δ H = 14.7 + (20 - 10) \times \frac{100}{1000} = 15.7 k J$

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