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Q.

A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per nucleon is

(Given : 1 a.m.u = 931 MeV)

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a

2.67 MeV

b

6.675 MeV

c

26.7 MeV

d

13.35 MeV

answer is B.

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Detailed Solution

Mass defect Δm=0.02866 a.m.u. 

Energy= 0.02866 x 931 = 26.7 MeV

As H2 1 +H2 1 →2He4

Energy liberated per nucleon =26.74=6.675 MeV

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