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Q.

A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per nucleon is
(Given : 1 a.m.u = 931 MeV)

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a

26.7 MeV

b

6.675 MeV

c

13.35 MeV

d

2.67 MeV

answer is B.

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Detailed Solution

Mass defect $Δm = 0.02866 a.m.u.$

Energy= 0.02866 x 931 = 26.7 MeV

As ${}_{1}{H^{2}} + {}_{1}{H^{2}} \to_{2} {He}^{4}$

Energy liberated per nucleon $= \frac{26.7}{4} = 6.675 MeV$

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