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A certain metallic surface is illuminated with monochromatic light of wavelength $λ$ .The stopping potential for photo – electric current for this light is $3 V_{0}$ . If the same surface is illuminated with light of wavelength $2 λ$ , the stopping potential is $V_{0}$ . The threshold wavelength for this surface for the photoelectric effect is

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$\frac{λ}{6}$

$6 λ$

$\frac{λ}{4}$

$4 λ$

answer is B.

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Detailed Solution

$3 e V_{0} = h c (\frac{1}{λ} - \frac{1}{λ_{0}})$

$e V_{0} = h c (\frac{1}{2 λ} - \frac{1}{λ_{0}}) \Rightarrow λ_{0} = 4 λ$

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