A certain organic substance used as a solvent in many reactions contains carbon, hydrogen, oxygen, and sulfur. The weight % of hydrogen in the compound is 7.7. The weight ratio $C : O : S = 3 : 2 : 4$ . What is the least possible molar mass of the compound?

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answer is D.

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Detailed Solution

Suppose the mass of compound

$\begin{array}{ll} H \to \frac{7.7}{1} = 7.7 C \to \frac{30.76}{12} = 2.56 \\ O \to \frac{20.51}{16} = 1.28 S \to \frac{41.02}{32} = 1.28 \\ C_{2} H_{6} OS \Rightarrow E.F. \end{array}$

Mass % of $H = 7.7$

Mass % of $C = 2.56$

Mass % of $O = 1.28$

Mass % of $S = 1.28$

Thus, the molar mass of the compound is 78.

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