A certain reaction is exothermic by 220 kJ and does 10 kJ of work. What is the change in the internal energy of the system at constant temperature?

Given: 

$q=-220 KJ$ (heat released)
work done, $\omega =10\mathrm{kJ}, \mathrm{\Delta }U=?$ 
as work done by system                 at constant temp.
 By 1st law of Thermodynamics

$=q+w=$

$\begin{array}{l}\mathrm{\Delta }U=-220-10\\ =-230\mathrm{kJ}\end{array}$

$\begin{array}{l}\mathrm{\Delta }H=\mathrm{\Delta }U+\mathrm{\Delta }nRT\\ -220=\mathrm{\Delta }U+10\end{array}$