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Q.

A chain of 100 links is 1 m long and has a mass of 2kg. With the ends fastened together it is set rotating at 3000 rpm, in a horizontal plan. The centripetal force (in N) on each link is ( take $π = 3.14$ )

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answer is 314.

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Detailed Solution

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$M = 2 kg l = 1 m$

Mass of each link = $\frac{M}{100} = 0.02 kg$

Radius $= \frac{l}{2 π} = \frac{1}{2 π}$

$ω = 3000 rpm = 3000 \times \frac{2 π}{60} rad / \sec$

$F = mr ω^{2}$

$F = 0.02 \times \frac{1}{2 π} \times (100 π)^{2}$

$= 100 π$

$F = 314 N$

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