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A charge $16 μC$ flows from point A to B, work done on charge is $16 \times 10^{- 3} . W$ hich of the following option is correct for $V_{A}, t$ he potential of A if potential of B is $V_{B} = 1100 volt$ ?

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50 V

150 V

200 V

100 V

answer is D.

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Detailed Solution

A charge

16 μC

flows from point A to B, work done on charge is

16 \times 10^{- 3} .

The potential of A (

V_{A})

100 V if

potential of B is

V_{B} = 1100 volt

.
Here charge,

q = 16 μC

; work done on charge,

w = 16 \times 10^{- 3} J

and potential of B is given as

V_{B} = 1100 volt

. Therefore, potential at point A will be-

V_{B} - V_{A} = \frac{work done}{charge}

∴

1100 - V_{A} = \frac{16 \times 10^{- 3}}{16 \times 10^{- 6}}

solving this equation, we get-

V_{A} = 100

volt.

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