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Q.

A charge +2q moves vertically upwards with speed v, a second charge q moves horizontally to the right with the same speed v, and a third charge + q moves horizontally to the right with the same speed v. The point P is located at a perpendicular distance a away from each charge as
shown in the figure. The magnetic field at point P is

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a

Into the page with magnitude μ04π  4qva2 

b

Into the page with magnitude μ04π  2qva2 

c

Out of the page with magnitude μ04π  4qva2

d

Out of the page with magnitude μ04π  2qva2

answer is D.

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Detailed Solution

BP=Bq+B2q+Bq=μ04πqva2    +μ04π2qva2    +μ04πqva2    =μ04π4qva2

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