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A charge of $1 μ C$ is divided into two point positive charges such that their charges are in the ratio of 2 : 3. These two charges are kept at a distance 1m apart in vacuum. The electric force between them is ______m N

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0.0216

0.216

2.16

21.6

answer is D.

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Detailed Solution

$q_{1} = \frac{2 q}{5} = \frac{2}{5} \times 10^{- 6} C; q_{2} = \frac{3 q}{5} = \frac{3}{5} \times 10^{- 6} C$

$F = \frac{q_{1} q_{2}}{r^{2}} \times 9 \times 10^{9} = 0.00216 N$

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