Q.

A charge of +10μC  and mass of 1gm is moving with velocity of 106 m/s at an angle of 45° to x & y axis as shown. In this case it experiences a magnetic force along – ve z – direction. If it were projected with 106m/s  along +ve z – direction, it would experience a magnetic force of 102N  in +ve x-direction. The magnetic field B   is:
 

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a

103Tj^

b

103Ti^

c

103T(i^+j^)

d

103T(j^+k^)

answer is D.

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Detailed Solution

q=10μC=105C    m = 103kg v=106[12i^+12j^] 

 F=q[v¯×B¯]

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