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A charge of 2 x 10^-2 C moves at 50 revolution per second in a circle of diameter 2m. The current linked with the circuit will be:

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2 $π$ A

0.4A

0.6A

answer is A.

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Detailed Solution

Charge = 2 x 10^-2 C
Time period I revolution $T = \frac{1}{50}$
Current $= \frac{Q}{t} = \frac{2 \times 10^{- 2}}{(1 / 50)} = 1 A$

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