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Q.

A charge of mass ‘m’ charge ‘2e’ is released from rest in a uniform electric field of strength ‘E’ . The time taken by it to travel a distance ‘d’ in the field is

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a

$\sqrt{\frac{2 dm}{Ee}}$

b

$\sqrt{\frac{2 Ee}{dm}}$

c

$\sqrt{\frac{dm}{Ee}}$

d

$\sqrt{\frac{2 dE}{me}}$

answer is A.

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Detailed Solution

$a = \frac{F}{m} = \frac{2 eE}{m}; s = \frac{1}{2} {at}^{2} \Rightarrow t = \sqrt{\frac{2 s}{a}} = \sqrt{\frac{md}{eE}}$

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A charge of mass ‘m’ charge ‘2e’ is released from rest in a uniform electric field of strength ‘E’ . The time taken by it to travel a distance ‘d’ in the field is