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Q.

A charge of mass ‘m’ charge ‘2e’ is released from rest in a uniform electric field of strength ‘E’ . The time taken by it to travel a distance ‘d’ in the field is

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a

2dmEe

b

2Eedm

c

dmEe

d

2dEme

answer is A.

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Detailed Solution

a=Fm=2eEm;s=12at2⇒t=2sa=mdeE

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