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Q.

A charge of $4 μC$ is to be divided into two. The distance between the two divided charges is constant. The magnitude of the divided charges so that the force between them is maximum, will be:

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a

$1.5 μC and 2.5 μC$

b

$1 μC and 3 μC$

c

$2 μC and 2 μC$

d

$0 and 4 μC$

answer is B.

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Detailed Solution

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Question Image

$\begin{array}{l} F = \frac{Kq (4 - q)}{d^{2}} \end{array}$

The maximum value of F is obtained when $\frac{dF}{dq}$ is zero

$\frac{dF}{dq}$ $= \frac{K}{d^{2}} [4 - 2 q] = 0 \Rightarrow q = 2$

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