Q.

A charge particle of charge q, mass m is moving with initial velocity ‘v’ as shown in  figure in a uniform magnetic field B  k^. Select the correct alternative / alternatives:-

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a

Distance travelled in magnetic field is πmV3qB

b

The particle will never come out of magnetic field

c

Velocity of particle when it comes out from magnetic field is V=vcos300i^vsin300j^

d

Time for which the particle was in magnetic field is πm3qB

answer is B, C.

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Detailed Solution

 

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velocity will be '

vcos 60i^+vsin 60j^

ARC AB = π3r=πmV3qB   Time ‘t’ 

= (12π)(π3)=T6=πm3qB

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