A charge particle q is projected in an electric field produced by a fixed point charge Q as shown in figure. Mark the correct statements.
 

The path traced by q is shown in figure. The path is curvilinear and acceleration is due to the force exerted by Q on q. The separation between them is minimum if relative
velocity of the particle along the line joining them is zero. Let d be the minimum separation between them. As torque about Q is zero, angular momentum remains  conserved.

$\mathrm{mua}=\mathrm{mvd}\text{ or }\mathrm{v}=\frac{\mathrm{ua}}{\mathrm{d}}$
From energy conservation law, $\frac{{\mathrm{mu}}^2}{2}=\frac{{\mathrm{mv}}^2}{2}+\frac{1}{4{\mathrm{\pi \epsilon }}_0}\frac{\mathrm{qQ}}{\mathrm{d}}$