Q.

A charge Q is distributed over two concentric hollow spheres of radii r and (R>r) such that the surface densities are equal. The potential at the common center is

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a

QR+r

b

Q(R+r)4πε0(R2+r2)

c

Q(R2+r2)4πε0(R+r)

d

Zero

answer is D.

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Detailed Solution

If q1  and q2  are the charge on spheres of radius r and R, respectively, in accordance with conservation of charge,

Q=q1+q2                         ….. (i)

and according to the given problem, σ1=σ2

i.e, q14πr2=q24πR2q1q2=r2R2                                 …… (ii)

So, (i) and (ii) give

q1=Qr2(R2+r2)  and q2=QR2(R2+r2)

Potential at common center

V=14πε0[q1r+q2R]

=14πε0[Qr(R2+r2)+QR(R2+r2)]=14πε0.Q(R+r)(R2+r2)

 

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A charge Q is distributed over two concentric hollow spheres of radii r and (R>r) such that the surface densities are equal. The potential at the common center is