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A charge Q is at the centre of a semicircle of diameter AB. If work done in moving a charge q along the semicircle is W₁ and work done in moving the same charge q along the path ACB is W₂, then

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W₁ = W₂ $\neq$ 0

W₁ < W₂

W₁ = W₂ = 0

W₁ > W₂

answer is D.

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Detailed Solution

As the electric field is a conservative field, the work done in moving a charge of 'q' will only depend on the initial and final positions of the charge.

In both the paths the initial and final positions are same, so W₁ = W₂ $\neq$ 0( since the path is not a closed loop)

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