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Q.

A charge +q is fixed at each of the points x=x0x=3x0,x=5x0 on the x - axis and a charge-q is fixed at each of the points x=2x0,x=4x0,x=6x0. Here x0 is a positive constant. Take the electric potential at a point due to a charge Q at a distance r from it to be Q4π0r. Then the potential at the origin due to the above system of charges is

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a

b

qloge(2)4π0x0

c

0

d

q8π0x0loge(2)

answer is D.

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Detailed Solution

V=q4π01x012x0+13x014x0+=q4π0x0112+1314+=q4π0x0log(2)

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