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Q.

A charge Q is placed at each of the two opposite corners of a square. A charge q is placed at each of the other two corners. If the resultant force on Q is Zero, then

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a

$Q = \sqrt{2} q$

b

$Q = 2 \sqrt{2} q$

c

$Q = - 2 \sqrt{2} q$

d

$Q = - \sqrt{2} q$

answer is D.

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Detailed Solution

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Question Image

from the diagram

$\sqrt{2} F_{1} = F_{2}$

K $\sqrt{2} K \frac{qQ}{r^{2}} = K \frac{Q^{2}}{2 r^{2}}$

$Q = - 2 \sqrt{2} q$

they have to be opposite type of charges to cancel.

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