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Q.

A charge q is placed at one corner of a cube as shown in figure. The flux of electrostatic field E through the shaded area is

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a

$\frac{q}{48 ε_{0}}$

b

$\frac{q}{4 ε_{0}}$

c

$\frac{q}{8 ε_{0}}$

d

$\frac{q}{24 ε_{0}}$

answer is D.

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Detailed Solution

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Net flux passing through a closed surface depends upon net charge enclosed by the surface.

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