A charge q is placed at the centre of the open end of cylindrical vessel. Find the flux of the electric field through the surface of the vessel.

Given Data: A charge q is placed at the centre of the open end of cylindrical vessel

Concept Used: Gauss Law

Detailed Solution:

Here, surface area of cylindrical vessel = half of total surface area 

So, electric flux $=(1/2)$ of total electric flux

By Gauss law,

total flux, $\mathrm{\varphi }=\frac{\mathrm{q}}{{\mathrm{ϵ}}_0}$

So, required flux ${\mathrm{\varphi }}^{\text{'}}=\frac{\mathrm{q}}{2{\mathrm{ϵ}}_0}$