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A charge q is placed at the centre of the open end of cylindrical vessel. Find the flux of the electric field through the surface of the vessel.

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a
q2ϵ0
b
qϵ0
c
q3ϵ0
d
zero

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detailed solution

Correct option is A

Given Data: A charge q is placed at the centre of the open end of cylindrical vessel

Concept Used: Gauss Law

Detailed Solution:

Here, surface area of cylindrical vessel = half of total surface area 

So, electric flux =(1/2) of total electric flux

By Gauss law,

total flux, ϕ=qϵ0

So, required flux ϕ'=q2ϵ0

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